On which does the convergence capacity of a l | vedclass

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(C) The convergence capacity of a lens is defined by its power $P$,which is given by the Lens Maker's formula: $P = \frac{1}{f} = (n - 1) \left( \frac

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Both $(A)$ and $(B)$

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(C) The convergence capacity of a lens is defined by its power $P$,which is given by the Lens Maker's formula: $P = \frac{1}{f} = (n - 1) \left( \frac{1}{R_1} - \frac{1}{R_2} \right)$.Here,$n$ is the refractive index of the lens material relative to the surrounding medium,and $R_1$ and $R_2$ are the radii of curvature of the two surfaces of the lens.Since the power $P$ depends on both the refractive index $n$ and the radii of curvature $R_1$ and $R_2$,the convergence capacity depends on both factors.Therefore,the correct option is $C$.

On which does the convergence capacity of a lens depend?

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